Bingo! dBFS is, without any additional information, ambiguous.
dB is an RMS power ratio. That's it, and that's all it will ever be, in spite of some mis-use along the way<G>.
0 dBFS in the digital domain refers to "all bits on" - the maximum instantaneous value that can be represented. Among other things that means it is is a peak value, so we will need to (later) change it to RMS.
0 dBFS, with the addition of the analog domain, still represents the maximum value that can be represented, but now we assume that it is also the maximum instantaneous voltage that can be produced by a D/A converter (or the maximum value that can be read by an A/D converter.) And that is a function of the converter architecture, and the power supply.
Do you see where this gets complex?
So what most folks have settled on is simply this:
1) there is no direct correlation between dBFS and dBu or dBV, it must be established on a system by system basis.
2) one needs to set 0VU (an entirely different concept) to be equal to some level lower than 0 dBFS. The common wisdom sees to hold that it should be somewhere between -14 dBFS and -18 dBFS, maybe -20 dBFS. The difference between the 0 VU reference and 0 dBFS is your headroom.
make sense?